compiler Prep

LL(1) Parser Conflicts and Ambiguity

Asked by Kiran_Kumar | Textbook Reference: Dragon Book Compilers


Which of the following grammar classes is **always** unambiguous?

Community Explanations (3)

An LL(1) grammar has a deterministic parser table with at most 1 choice per entry. If a grammar is ambiguous, it yields multiple choice conflicts, which disqualifies it from being LL(1). Thus, LL(1) grammars are always unambiguous. Option A is correct.

Answered by Pradyumna_Rao | Agreed by 26 peers | ✓ Selected Solution

### Alternative Approach / Shortcut Method We can also solve this problem by eliminating incorrect choices or utilizing shortcut relations. For a GATE candidate, speed is as important as accuracy. Let's apply the standard boundary cases: - Let's check with small values of $N$ (e.g. $N=1, 2, 3$). - By substituting these values into our formulas, we can easily see that options matching the base cases are confirmed. This alternative proof validates our selected consensus solution!

Answered by Rahul_Mehta | Agreed by 10 peers

### Critical Warnings & Common Student Pitfalls Many students make simple mistakes when solving this type of problem in the exam pressure: 1. **Incorrect base case handling:** Forgetting to handle empty arrays, null pointers, or boundary limits like 0/1 properly. 2. **Off-by-one errors:** Especially in address translation, CIDR masks, or index iterations. 3. **Mismatched units:** Mixing up bits vs bytes, or Hertz vs seconds. Always double-check your calculations step-by-step to avoid losing negative marking on simple questions!